kerkerj
Array
宣告
// var VARIABLE_NAME: [TYPE] = .....
var fruits: [String] = ["apple", "banana"]
var nums: [Int] = [1, 2]
// 或是讓 Swift 自行判斷類型:
var fruits = ["apple", "banana"]
var nums = [1, 2]
// 初始化:
var cars = [String]()
ps. Beta 版時的寫法是 var fruits: String[]
現在已經變成了 var fruits: [String]
操作
// 判斷該陣列是否有值,回傳 true 或 false
fruits.isEmpty
// 增加元素
fruits.append("watermelon")
fruits += ["lemon"]
// 取值
fruits[0]
fruits[0...2]
// 刪除值 - 將 apple 移除,banana 會自動補上
fruits.removeAtIndex(0)
fruits[0]
// 兩個陣列合併 (必須相同類別 e.g. String)
fruits + cars
// 陣列元素數量
fruits.count
Dictionary
宣告
由於 Dictionary 是 key/value 為一組 (pair),
因此宣告時必須宣告 key 和 value 分別是哪種型別
var httpStatus: Dictionary<Int, String> = Dictionary<Int, String>()
var httpStatus: Dictionary<Int, String> = [200: "Success", 404: "Not found"]
操作
// 一樣有 isEmpty 方法
httpStatus.isEmpty
// 取值
httpStatus[200] // = "Success"
// 加入值
httpStatus[500] = "Internal Server Error"
// 修改值
httpStatus[200] = "True"
httpStatus.updateValue("internal server error", forKey: 500)
// 刪除值
httpStatus.removeValueForKey(200)
// 字典元素數量
httpStatus.count
Controll Flow
For loop
for fruit in fruits {
println(fruit)
}
for var index = 0; index < fruits.count; ++index {
println(fruits[index])
}
While
var index = 0
while index < fruits.count {
println(fruits[index])
index++
}
Do-while
var index = 0
do {
println(fruits[index])
index++
} while (index < fruits.count)
If
var index = 5566
if index = 5566 {
println("5566 不能亡")
}
if index = 5566 {
println("5566 不能亡")
} else {
println("You are not 5566")
}
if index = 5566 {
println("5566 不能亡")
} else if index < 5566 {
println("You are less than 5566")
} else {
println("You are bigger than 5566")
}
Switch
var index = 0
switch index {
case 0, 1, 2
println("small")
case 8, 9, 11
println("big")
default:
println("others")
}
引入 Tuple
let httpStatus = (200, "Success")
switch httpStatus {
case (let statusCode, "Error"):
println("(\(statusCode)) is Error")
case (200, let msg):
println("(\(msg))'s statusCode is 200")
}
Switch - break, continue, fallthrough
Continue
continue 會使該次的 loop 停止,並繼續執行下一個 loop
continue 不存在於單一的 switch, 只會在 loop 裡的 switch 語句時才能使用
var fruits = ["apple", "banana", "lemon", "waterlemon", "orange"]
for fruit in fruits {
println("Start")
switch fruit {
case "banana":
continue
default:
println(fruit)
}
println("End")
}
Start 和 End 理論上都要被印五次,
但是加入了 continue 後,banana case 當次 loop 的 End 就沒有被執行了
Break
通常是用在不想處理某個 case 或,特別想要處理時 (?) 反之嘛 XD
當使用了 break,會立即中斷 switch 程式碼的執行,並且跳到 switch 區塊程式碼結束的大括號後 (}) 的第一行程式
暫時想不到什麼好例子….
先借別人的例子來用吧:
let numberSymbol: Character = "三" // 簡體中文裡的數字 3
var possibleIntegerValue: Int?
switch numberSymbol {
case "1", "١", "一", "๑":
possibleIntegerValue = 1
case "2", "٢", "二", "๒":
possibleIntegerValue = 2
case "3", "٣", "三", "๓":
possibleIntegerValue = 3
case "4", "٤", "四", "๔":
possibleIntegerValue = 4
default:
break
}
if let integerValue = possibleIntegerValue {
println("The integer value of \(numberSymbol) is \(integerValue).")
} else {
println("An integer value could not be found for \(numberSymbol).")
}
// 輸出 "The integer value of 三 is 3.
Fallthrough
在 Swift 中,掃到第一個符合的 case 後,就會中斷 switch 的執行了,避免掉入一些 case 處理的錯誤
而 fallthrough, 很有趣, 宣告後,會讓 switch 繼續掃下一個 case
let num = 5
var description = "\(num) is"
switch num {
case 2, 3, 5, 7, 11, 13, 17, 19:
description += " a prime, also"
fallthrough
case 5:
println("I'm here")
default:
description += " an integer."
}
println(description)
// I'm here
// 5 is a prime, also an integer.